1)已知x+y=6,xy=-3,则x^2y+xy^=?2)分解因式3(a-b)^2 + 6(b-a)
(1)已知x+y=6,xy=-3,则x^2y+xy^=?(2)分解因式3(a-b)^2 + 6(b-a)
人气:229 ℃ 时间:2020-09-30 13:52:03
解答
(1)x^2y+xy^2=xy(x+y)=-3*6=-18
(2) 3(a-b)^2 + 6(b-a)= 3(a-b)^2 - 6(a-b)= 3{(a-b)^2 - 2(a-b)}=
3(a-b){(a-b)- 2}=3(a-b)(a-b-2)
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