2√3/(1/√6 +1/√2)=2√3/((1+√3)/√6)=2√3*(√6/(1+√3)=2√2/(1+√3)=2√2(1-√3)/(1+√3)(1+√3)
=√2(1-√3)=√2-√62��3*(��6/(1+��3)=2��2/(1+��3)=2��3*(��6/(1+��3)=2*3*(��2/(1+��3)=6��2/(1+��3)=6��2*((1-��3)/(1+��3)(1-��3))=-3��2(1-��3)=3(��6-��2)д���ˣ���Ǹ��