1/(x+3)+1/(6-2x)=(3x-15)/(2x^2-18)
1/(x+3)-1/(2x-6)=(3x-15)/(2x^2-18)
1/(x+3)-1/[2(x-3)]=(3x-15)/[2(x-3)(x+3)]
2(x-3)-(x+3)=(3x-15)
2x-6-x-3=3x-15
x-9=3x-15
3x-x=15-9
2x=6
x=3
经检验x=3是增根,所以方程无解