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9X^8+3分之1X^2
人气:492 ℃ 时间:2020-04-13 20:08:31
解答
9x^8+x^2/3
=(x^2/3)*(27x^6+1)
=(x^2/3)*[(3x^2)^3+1^3]
=(x^2/3)(3x^2+1)(9x^4-3x^2+1)
=x^2*(3x^2+1)(9x^4-3x^2+1)/3.
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