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解方程(3/x)+(1/x-1)+(4/x-2)+(4/x-3)+(1/x-4)+(3/x-5)=0谢谢了,
人气:197 ℃ 时间:2020-04-16 11:06:06
解答
是3/x+1/(x-1)+4/(x-2)+4/(x-3)+1/(x-4)+3/(x-5)=0吧?不然也太简单了.3/x+1/(x-1)+4/(x-2)+4/(x-3)+1/(x-4)+3/(x-5)=0的解共五个,为:x=5/2,x=(5±sqrt(7))/2,x=(5±sqrt(17))/2.
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