(x+y)^2=11,(x-y)^2=7,求xy的值
人气:261 ℃ 时间:2020-04-03 06:39:20
解答
∵(X+Y)=X+2XY+Y=11 (X-Y)=X-2XY+Y=7 ∴(X+Y)-(X-Y)=4XY=11-7=4 ∴XY=1
推荐
- 若X+Y=0,XY=11,求X^2-XY+Y^2的值.
- 若(x+y)^2=11,(x-y)^2=7,则xy的值为________.
- 若x^2+xy+y=5,y^2+xy+x=7,则x+y的值为
- 若(x+y)^2=11,(x-y)^2=7,则xy的值是多少
- 已知(x+y)^2=11,(x-y)^2=7,求x^2+y^2及xy的值
- How often do you get this magazine?
- 初一英语50词作文两篇
- 英语完形填空,看不懂
猜你喜欢