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求sin2/7π+sin3/7π-sinπ/7的值
(根号7)/2,怎么算的
人气:292 ℃ 时间:2020-06-07 16:19:46
解答
sin(2π/7)+sin(3π/7)-sin(π/7)=sin(5π/14-π/14)+sin(5π/14+π/14)-sinπ/7=sin5π/14cosπ/14-cos5π/14sinπ/14+sin5π/14cosπ/14+cos5π/14sinπ/14-sinπ/7=2sin5π/14cosπ/14-sinπ/7=2cos(2π/14...
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