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若(sinθ)^6+(cosθ)^6=13/16,则sin2θ=
人气:285 ℃ 时间:2020-08-25 10:44:25
解答
(sinθ)^6+(cosθ)^6=13/16[(sinθ)^2+(cosθ)^2][(sinθ)^4-(sinθ)^2(cosθ)^2+(cosθ)^4]=13/16(sinθ)^4-(sinθ)^2(cosθ)^2+(cosθ)^4=13/16[(sinθ)^2+(cosθ)^2]^2-3(sinθ)^2(cosθ)^2=13/161-3(sinθcosθ)...
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