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解二元一次方程组2x+3y/2=3x+2y/5+2 3(2x+3y)/2=2(3x+2y)/5+6
人气:110 ℃ 时间:2019-08-18 19:06:10
解答
(2x+3y)/2=(3x+2y)/5+2 ① 3(2x+3y)/2=2(3x+2y)/5+6 ②①得,2x+3y=2(3x+2y)/5+4 ③代入②得,3(3x+2y)/5+6=2(3x+2y)/5+63x+2y=0x=-2y/3④代入③得,-4y/3+3y=4y=12/5代入④,得 x=-8/5∴方程组的解是:x=-8/5y=12/5...
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