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求y=ln(x+1)/(x-1)的反函数!
人气:427 ℃ 时间:2020-04-23 21:44:14
解答
(x+1)/(x-1)=e^y
(x+1)/(x-1)-1=e^y-1
2/(x-1)=e^y-1
x-1=2/(e^y-1)
x=(e^y+1)/(e^y-1)
反函数y=(e^x+1)/(e^x-1)呵呵,看懂啦
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