比较大小:2/(√6+4)和2√2-√6
人气:409 ℃ 时间:2020-05-20 22:29:19
解答
2/(√6+4)<2√2-√6. 证明如下:利用反证法,设2/(√6+4)≧2√2-√6,则:2(4-√6)/(16-6)≧2√2-√6,∴(4-√6)/5≧2√2-√6,∴4-√6≧10√2-5√6,∴4+4√6≧10√2,∴2+2√6≧5√2,∴√2+...
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