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1,若x+y+3=0,求3分之2-2x-2y+(-x-y)的平方 2,已知xy分之x+y=3,求-x+2xy-y分之2x-3xy+2y的值
人气:167 ℃ 时间:2019-08-21 22:46:59
解答
x+y+3=0,x+y=-3
3分之2-2x-2y+(-x-y)的平方
=【2-2(x+y)+(x+y)^2】/3
=(2-6+9)/3
=5/3
(x+y)/xy=3,x+y=3xy
(2x-3xy+2y)/(-x+2xy-y)
=[2(x+y)-3xy]/[2xy-(x+y)]
=3xy/(-xy)
=-3
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