如何因式分解3x*2-10xy 3y*2 9x 5y-12
人气：221 ℃ 时间：2019-10-17 03:48:13
解答
3x*2-10xy+3y*2+9x+5y-12
=(3x-y)(x-3y)+12x-4y-3x+9y-12
=(3x-y)(x-3y)+4(3x-y)-3x+9y-12
=(3x-y)(x-3y+4)-3(x-3y+4)
=(x-3y+4)(3x-y-3)
推荐
猜你喜欢
- 求函数y=xarctanx-ln根号下(1+x^2)的导数y'
- I saw a movie called Hero last night?的同义句
- 极限lim (1+x)ln(1+x)分之sinx = ? x→0
- 数列1,38,1,5,49,4,7,50,7,9,51,10,11,……的第100个数是多少?
- He saw the bag when his bike hit it.()
- 一个物体速度大小不变,方向一直在变,做曲线运动,那么它的合外力可不可能为恒力?
- 寓言故事读后感 500字左右
- What is the price of the dctionary?改为同义句
