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已知|xy-4|+(x-2y-2)²=0
⑴(-½xy)(x²-4xy+4y²)的值
⑵求(x+2y)²的值
人气:492 ℃ 时间:2020-05-19 07:18:24
解答
因为|xy-4|>=0,(x-2y-2)²>=0
所以由已知条件可得:、
xy-4=0
x-2y-2=0

xy=4
x-2y=2
从而可知
(-1/2xy)x²-4xy+4y²
=-2(x-2y)²
=-2*2²
=-8

(x+2y)²
=(x-2y)²+8xy
=4+8*4
=36
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