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已知|ab-2|与|b-1|互为相反数.求1/ab+1/(a+2)*(b+1)+1/(a+2)*(b+2)+...+1/(a+2010)*(b+2010)
人气:408 ℃ 时间:2020-07-04 19:51:25
解答
已知|ab-2|与|b-1|互为相反数.
b-1=0 b=1
ab-2=0 a=2
1/ab+1/(a+2)*(b+1)+1/(a+2)*(b+2)+...+1/(a+2010)*(b+2010)
=1/1x2+1/2x3+1/3x4+……+1/2011x2012
=1-1/2+1/2-1/3+1/3-1/4+……+1/2011-1/2012
=1-1/2012
=2011/2012
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