若已知|a+2|+|b-3|+|c-4|=0,则式子a+2b+3c的值为______.
人气:120 ℃ 时间:2020-01-28 13:11:28
解答
根据题意得,a+2=0,b-3=0,c-4=0,
解得a=-2,b=3,c=4,
所以,a+2b+3c=-2+2×3+3×4=-2+6+12=-2+18=-16.
故答案为:-16.
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