设A=2x^2-3xy+y^2-x+2y,B=4x^2-6xy+2y^2-3x-y.求B-2A；若|x-2a|+(y+3)^2=0,且B-2A=a,求a的值
人气：138 ℃ 时间：2019-08-21 00:33:35
解答
B-2A=(4x^2-6xy+2y^2-3x-y)-2(2x^2-3xy+y^2-x+2y)=-x-5y
∵若|x-2a|+(y+3)^2=0,∴x=2a,y=-3,∵且B-2A=a,∴-x-5y=a,-2a+15=a,a=5
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