若x-y不等于0,2x-3y=0,则分式(10x-11y)/(x-y)的值是（）?(10x-11y)/(x-y) =[(8x-8y)+(2x-3y)]/(x-y) =8
为什么8X-8Y=8？(10x-11y)/(x-y)
=[(8x-8y)+(2x-3y)]/(x-y)
=8+(2x-3y)]/(x-y)
=8+0
=8
人气：454 ℃ 时间：2020-05-06 12:43:24
解答
=[(8x-8y)+(2x-3y)]/(x-y)
=[(8x-8y)+0]/(x-y)
=(8x-8y)/x-y
=8(x-y)/x-y(这是乘法分配律)
=8(约分 同时除以x-y)
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