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数学
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若x2+y2+2x-8y+17=0,求(-2x)的y次方的值
人气:407 ℃ 时间:2020-03-30 16:34:14
解答
x2+y2+2x-8y+17=0
x2+2x+1+y2-8y+16=0
(x+1)2+(y-4)2=0
x=-1 y=4
(-2x)^y=(-2*(-1))^4=2^4=16
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