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函数 (15 16:59:54)
已知45°
人气:269 ℃ 时间:2020-05-11 00:33:46
解答
√[1/2+1/2√(1/2+1/2cos2α)]
=√[1/2+1/2√(cos^2α)]
=√[1/2+1/2|cosα|]
= √[cos^2(α/2)]
=|cos(a/2)|;或
√[1/2+1/2√(1/2+1/2cos2α)]
=√[1/2+1/2|cosα|]
= √[sin^2(α/2)]
=|sin(a/2)|.
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