x^2-3x/x^4-6x^3+9x^2(约分)
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人气:454 ℃ 时间:2020-05-20 13:37:40
解答
x^2-3x/x^4-6x^3+9x^2 分子分母同除以x,
=(x-3)/(x³-6x²+9x) 提出分母公因式x后,再配方,
=(x-3)/x(x-3)² 分子分母同除以x-3
=1/(x²-3x)
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