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一.已知X^2+X-1=0,求X^3-2X+4的值
二.已知a^2-3a+1=0,求a^4+1/a^4的值
人气:136 ℃ 时间:2020-03-29 04:47:19
解答
X^3-2X+4
=X(X^2+X-1)-(X^2+X-1)+3
=3
a^4+1/a^4
=a^4+1/a^4+2-2
=(a^2+1/a^2)^2-2
因为a^2-3a+1=0 a不等于0
a^2+1=3a两边同除以a
所以a+1/a=3
所以(a^2+1/a^2)^2-2
=[(a+1/a)^2-2]^2-2
=(3*3-2)^2-2
=47
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