急呀,帮忙计算一下.要过程1/101*103+1/103*105+1/105*107+.1//199*201
人气：338 ℃ 时间：2019-08-23 10:15:09
解答
原式=1/2（1/101-1/103+1/103-1/105+1/105-1/107+.-1/109+1/109-1/201)=50/(201*101),每个1/n*(n+2)都可以分解为1/2[1/n-1/(n+2)]
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