根据de Moivre公式,如果复数z = r (cosx + isinx ),那么z^(1/n) = r^(1/n) [ cos( (x+2kπ)/n ) + i sin( (x+2kπ)/n ) ],k = 0,1,2,...,n-1.这里r = 2sqrt(2),x = -π/4,n = 3,代入即可求出以下三个立方根：k = 0,(...