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计算:8ab÷12a²b;(2x/3y)²·(3y/4x)³
人气:343 ℃ 时间:2020-02-04 06:05:52
解答
8ab÷12a²b=8ab÷12[a(ab)]=8/(12a)=2/(3a)
(2x/3y)²·(3y/4x)³
=(2x/3y)²·(3y/4x)²·(3y/4x)
=[(2x/3y)·(3y/4x)]²·(3y/4x)
=(1/4)·(3y/4x)
=·3y/(16x)
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