若|x-1|+|y-2|=0,求1/xy+1/(x+1)(y+1)+1/(x+2)(y+2)+.+1/(x+2009)(y+2009)的值
十分钟内的答案,经过认可,
人气：170 ℃ 时间：2020-02-05 07:19:52
解答
|x-1|+|y-2|=0
x=1,y=2
1/xy+1/(x+1)(y+1)+1/(x+2)(y+2)+.+1/(x+2009)(y+2009)
=1/2+1/6+1/12+.+1/(2010*2011)
=1-1/2+1/2-1/3+.+1/2010-1/2011
=1-1/2011
=2010/2011
推荐
- 若x＝1,y=2,求1／xy＋1／﹙x+1﹚·﹙y+1﹚＋1／﹙x＋2﹚·﹙y＋2﹚…………+1／﹙x+2009)·(y+2009)的值
- |X-1|与|Y-2|互为相反数,计算1/XY+1/(X+1)(Y+1)+---+1/(X+2009)(Y+2009)的值
- 若x^2+y^2+2x-8y+17=0,求 x^2009+xy的值
- 设A={x,x^2,xy},B={1,x,y},且A=B,求x^2009+y^2010的值
- 若|x-1|+|y-2|=0,求1/xy+1/(x+1)(y+1)+1/(x+2)(y+2)+.+1/(x+2009)(y+2009)的值
- He ___(teach) you English well,doesn't he?
- 露西用英语怎么说?We can't put our bikes over there.改祈使句
- 闻一多（打一字）
猜你喜欢
