稳定后,滑轮两侧绳子的长度、倾角和拉力T均相等
绳子与水平方向夹角cosα=(4/2)/(5/2) = 4/5,sinα=√(1-cos^2α)=3/5
Tsinα+Tsinα=mg
绳子张力T = mg/(2sinα) = 2*10/(2*3/5) = 50/3 N