繁分式 已知(x²+x-3)\[(x-1)(x-2)(x-3)]=A\(x-1)+B\(x-2)+C\(x-3),求A,B,C的
人气:149 ℃ 时间:2020-05-23 02:37:31
解答
( x^+ x - 3 ) / ( (x-1) (x-2) (x-3) )=A / (X-1)+B/ ( X-2) + C/ (x - 3 )=[A(x^-5x+6)+B(x^-4x+3)+C(x^-3x+2)]/[(x-1)(x-2)(x-3)]则x^+ x - 3=A(x^-5x+6)+B(x^-4x+3)+C(x^-3x+2)得到三个方程A+B+C=1,-5A-4B-3C=...
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