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[x^2-y^2(x-4y)(x+4y)-x^2-y^2(x-2y)^2]/[-(2xy)^2]
[x^2y^2(x-4y)(x+4y)-x^2y^2(x-2y)^2]
人气:126 ℃ 时间:2020-06-05 14:15:27
解答
[x²y²(x-4y)(x+4y)-x²y²(x-2y)²]/[-(2xy)²]
=x²y²(x²-16y²-x²+4xy-4y²)/-4x²y²
=20y²-4xy/4
=5y²-xy
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