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计算:(lg根号下27+lg8-lg根号下1000)\lg1.2
人气:181 ℃ 时间:2019-10-26 05:52:29
解答
解; (lg√27+lg8-lg√1000)/lg1.2
=(lg3^3/2+lg2^3-lg10^3/2)/lg1.2
=(3/2lg3+3lg2-3/2lg2-3/2lg5)/lg1.2
=(3/2lg3+3/2lg2-3/2lg5)/lg1.2
=3/2(lg3+lg2-lg5)/lg1.2
=3/2(lg6-lg5)/lg1.2
3/2lg6/5/lg1.2
=3/2lg1.2/lg1.2
=3/2
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