ab+a-b-1/a2b2-a2-b2+1=[a(b+1)-(b+1)]/[a²(b²-1)-(b²-1)]=(b+1)(a-1)/(b²-1)(a²-1)=1/(b-1)(a+1)当b=0.03 a=99时原式=1/(1-0.03)(99+1)=1/97