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tan(π/8)-cot(π/8)=?
A.-2 B.-1 C.1 D.2
人气:305 ℃ 时间:2020-05-12 17:22:54
解答
tanπ/8-ctgπ/8
=(sinπ/8)/(cosπ/8)-(cosπ/8)/(sinπ/8)
=[(sinπ/8)^2-(cosπ/8)^2]/(sinπ/8*cosπ/8)
=(-cosπ/4)/[(1/2)*sinπ/4]
=-2
A.-2
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