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利用平方差求(x-y+1)(x+y-1)的值
人气:264 ℃ 时间:2020-04-23 03:54:52
解答
(x-y+1)(x+y-1)
=[x-(y-1)][x+(y-1)]
=x^2-(y-1)^2
=x^2-y^2+2y-1
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