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计算tanπ/12 / (1-tan^2π/12)=
人气:234 ℃ 时间:2020-09-23 10:10:48
解答
tanπ/12 / (1-tan^2π/12)
=1/2*(2tanπ/12) / (1-tan^2π/12)
=1/2*tan(π/12+π/12)
=1/2*tanπ/6
=1/2*√3/3
=√3/6
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