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求0°与360°之间所有满足3cos x = 8 tan x的角 x
人气:399 ℃ 时间:2020-06-21 06:19:46
解答
3cosx = 8sinx/cosx
3cos^2 - 8sinx = 0
3 (1-sin^2) - 8sin=0
3sin^2 + 8sin - 3 = 0
(3sin-1)(sin+3) = 0
sinx = 1/3
x = arcsin(1/3)
有两个(1,2象限)~19.5 和160.5
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