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数学
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7、极限lim(x→0) (1-3x)^1/x=
人气:263 ℃ 时间:2020-03-23 14:01:06
解答
令1/a=-3x
1/x=-3a
则a→∞
原式=lim(a→∞)(1+1/a)^(-3a)
=lim(a→∞)[(1+1/a)^a]^(-3)
=e^(-3)
=1/e³
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