这道题应该这样算：
1/n(n+1)=1/n-1/(n+1)
1/(1*2)+1/(2*3)+1/(3*4)+…+1/(98*99)+1/(99*100)
=1-1/2+1/2-1/3+1/3-1/4+…+1/98-1/99+1/99-1/100
=1-1/100
=99/100
回答完毕,希望我的回答能帮助到楼主!