甲数除以乙数,商是39,余数是6,且甲乙两数的差为310,求甲数、乙数各是多少?
人气：409 ℃ 时间：2019-09-16 23:37:00
解答
设乙为a则甲=39a+6
那么
39a+6-310=a
38a=304
a=8
那么甲为310+8=318
算术：
乙=（310-6）/（39-1）=8
甲=310+8=318
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