试求函数y=1/2*cos(πx+π/3)-sin(πx+5π/6)的单调递减区间.
人气:326 ℃ 时间:2019-12-10 19:28:49
解答
y=1/2*cos(πx+π/3)-sin[π-(πx+5π/6)]=1/2*cos(πx+π/3)-sin(-πx+π/6)=1/2*cos(πx+π/3)-cos[π/2-(-πx+π/6)]=1/2*cos(πx+π/3)-cos(πx+π/3)=-1/2*cos(πx+π/3)y递减则cos递增cosx增区间是(2kπ-π,2k...
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