a-b/a+b*a四次方-a²b²/a²-ab和 4x²-4xy+y²/2x+y÷(4x²-y²)
人气:167 ℃ 时间:2020-05-26 21:26:40
解答
a-b/a+b*a四次方-a²b²/a²-ab
=[(a-b)/(a+b)]*(a^4-a^2b^2)/(a^2-ab)
=[(a-b)/(a+b)]*a^2(a+b)(a-b)/a(a-b)
=a(a-b)
=a^2-ab
( 4x²-4xy+y²)/(2x+y)÷(4x²-y²)
=(2x-y)^2/[(2x+y)(2x+y)(2x-y)]
=(2x-y)/(2x+y)^2
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