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分解因式;1.x²-2x-3 2.x²-2xy+y²-2x+2y+1
人气:363 ℃ 时间:2020-05-12 16:23:18
解答
1.x²-2x-3
=(x-3)(x+1)
2.x²-2xy+y²-2x+2y+1
=(x-y)²-2(x-y)+1
=(x-y-1)²
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