十字相乘法的一道题
(X²+X)²-8(X²+X)+12
人气:488 ℃ 时间:2020-04-01 02:55:24
解答
原式=(x²+x)²-8(x²+x)+12,把(x²+x)看成整体
=[(x²+x)-2][(x²+x)-6]
=(x²+x-2)(x²+x-6)
=(x-1)(x+2)(x-2)(x+3)
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