V L HCl物质的量: V/22.4 mol
质量: 36.5V/22.4 g
溶液质量: a + 36.5V/22.4 g
1. w = (36.5V/22.4)/(a + 36.5V/22.4) = 36.5V/(22.4a + 36.5V)
2.
溶液体积: (a + 36.5V/22.4)/ρ mL = (a + 36.5V/22.4)/(1000ρ) L
c = (V/22.4)/[(a + 36.5V/22.4)/(1000ρ)]
= 1000ρV/(22.4a + 36.5V) mol/L
3.
题中已经给出,不用求.否则还需一个条件.
4.
10 mL溶液质量 10ρ g
含HCl: 10ρ*36.5V/(22.4a + 36.5V) = 365ρV/(22.4a + 36.5V)
加等体积水后, 溶液质量 10ρ + 10 g
溶液质量分数w' = [365ρV/(22.4a + 36.5V)]/(10ρ + 10)
= [ρ/(ρ + 1)][36.5V/(22.4a + 36.5V)]
=wρ/(ρ + 1)
ρ < 1时: w' < 0.5w
ρ = 1时: w' = 0.5w
ρ > 1时: w' > 0.5w