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2log3 2-log32/9+log3 8-5^log5 3
人气:166 ℃ 时间:2020-05-11 06:38:38
解答
应用公式:
①log3(M/N)=log3(M)-log3(N)
②log3(Mⁿ)=nlog3(M)
③M^logM(N)=N
2log3(2)-log3(2/9)+log3(8)-5^log5(3)
=2log3(2)-[log3(2)-log3(9)]+3log3(2)-3
=2log3(2)-log3(2)+2log3(3)+3log3(2)-3
=4log3(2)+2-3
=4log3(2)-1
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