limx→1ˉ(1-x)In(1-x) =limx→1ˉIn(1-x)/[1/(1-x)]使用洛必达法则=limx→1ˉ1/(1-x)/[1/(1-x)^2]=limx→1ˉ(1-x)=0limx→1{1/(x-1)-1/Inx}=limx→1{[lnx-(x-1)]/[（x-1)Inx]}洛必达法则=limx→1{[1/x-1)]/[Inx+(x-...