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极限lim(n->∞) n^(2/3)/[(n^2+n+7)^1/3]=1
人气:177 ℃ 时间:2020-04-09 21:27:18
解答
变换为(n^(2/3)/[(n^2+n+7)^1/3])^(3*(1/3))
变换为(n^2)/[(n^2+n+7)]^(1/3)
变换为(1)/[(1+(1/n)+(7/n))]^(1/3)
变换为(1)/[(1+(0)+(0))]^(1/3)
1
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