已知x=2-根号3分之2+根号3,y=2+根号3分之2-根号3,求值:2x^2-3xy+2y^2
人气:267 ℃ 时间:2019-08-19 14:18:14
解答
x=(2+√3)/(2-√3) 分母有理化
=(2+√3)²/[(2+√3)(2-√3)]
=(7+4√3)/(4-3)
=7+4√3
y=(2-√3)/(2+√3) 分母有理化
=(2-√3)²/[(2+√3)(2-√3)]
=(7-4√3)/(4-3)
=7-4√3
2x²-3xy+2y²
=(2x²-4xy+2y²)+xy
=2(x²-2xy+y²)+xy
=2(x-y)²+xy
=2[ (7+4√3)-(7-4√3) ]² +(7+4√3)(7-4√3)
=2×(8√3)² +49-48
=2×192 +1
=385
推荐
- 已知x=2-根号3分之2+根号3,y=2+根号3分之2-根号3,求值:2x^2-3xy+2y^2
- 已知x=(2+根号3)/(2-根号3),y=(2-根号3)/(2+根号3),求值:2x²-3xy+2y²
- 已知x=2-根号3分之2+根号3,y=2+根号3分之2-根号3,则代数式2x平方-3xy+2y平方?
- 已知(2x+3y-8)的平方+根号x-2y+3=0,求x+y分之3xy的值
- 已知x=2+根号3/2-根号3,y=2-根号3/2+根号3,求2x的平方-3xy+2y平方的值
- 一台彩色电视机原来售价1200元,现在比原来便宜了1/5,便宜了多少元?
- I work as a salesman which selling English Newspaper in University
- 设复数z=1/a+5+(a2+2a−15)i为实数时,则实数a的值是_.
猜你喜欢