> 数学 >
x→+0,lim(1/x)^(tanx)=?
人气:142 ℃ 时间:2019-10-11 07:45:02
解答
x→+0
lim(1/x)^(tanx)
=exp [lim (tanx)ln(1/x)]
=exp [lim xln(1/x)]
=exp [lim ln(1/x)/(1/x)]
=exp [lim (1/(1/x))(1/x)'/(1/x)']
=exp lim x
=e^0
=1
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版