x=3/2,y=4/3求x³-x²y+xy²-y²x+y³?有没有搞错?把-y²x+y³改成-y³我先算个吧原式=x²（x-y）+y²（x-y）=（x²+y²）（x-y）=[(x-y)²+2xy](x-y)x+y=17/6...x³-x²y+xy²-y²x+y³没错xy²-y²x=0啊。。。这样题目出了做啥？x³-x²y+y³=27/8-3+64/27=(3*27+64*8)/216=593/216