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因式分解 (x²+y²-a²)²-4x²y²
(x²+y²-a²)-4x²y²
人气:363 ℃ 时间:2020-03-29 17:42:47
解答
(x²+y²-a²)²-4x²y²=(x²+y²-a²+2xy)(x²+y²-a²-2xy)=[(x+y)²-a²][(x-y)²-a²]=(x+y+a)(x+y-a)(x-y+a)(x-y-a)再问你两个呗 (x²-2x)(x²-2x+2)+1和121(a+b)²-289(a-b)²谢谢!
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